Fonctions exponentielles et logarithmes - Partie 1#
Nom, prénom:
Note:
| Question | 1 | 2 | Total |
|---|---|---|---|
| Points | 3 | 3 | 6 |
| Obtenus |
Détails des calculs obligatoires. Attention au soin.
Réponse sous forme de valeur exacte simplifiée.
Calculatrice non autorisée.
Question 1 (3 pts)#
Calculez:
\(64^{-\frac{1}{3}} = \)
\(\log(10) = \)
\(\log_3(27) = \)
\(\log_2(\sqrt{2}) = \)
\(\log(\dfrac{1}{1000}) = \)
\(4^{\log_4(5)} = \)
Solution
\(64^{-\frac{1}{3}} = \dfrac{1}{4}\)
\(\log(10) = 1\)
\(\log_3(27) = 3\)
\(\log_2(\sqrt{2}) = \dfrac{1}{2}\)
\(\log(\dfrac{1}{1000}) = -3\)
\(4^{\log_4(5)} = 5\)
Question 2 (3 pts)#
Que vaut x ?
\(5^x = 125 \qquad x = \)
\(4^x = \dfrac{1}{16} \qquad x = \)
\(7^{3x} = 7^{6} \qquad x = \)
\(\log(x) = 4 \qquad x = \)
\(\log_x(49) = 2 \qquad x = \)
\(\log_3(x) = 0 \qquad x = \)
Solution
\(5^x = 125 \qquad x = 3\)
\(4^x = \dfrac{1}{16} \qquad x = -2\)
\(7^{3x} = 7^{6} \qquad x = 2\)
\(\log(x) = 4 \qquad x = 10\,000\)
\(\log_x(49) = 2 \qquad x = 7\)
\(\log_3(x) = 0 \qquad x = 1\)